No. Volts is the "pressure" of the electricity. If a single 3.6v led required 20 milliamps (amps is the "amount" of electricity) you would need to supply two of them with 40 milliamps but at 3.6 volts.
200 divided my 40 equals = 5
0.21
200 divided 40 equals = 5
2.5
5
40 divided by five equals eight, so the answer is 40. But sorry if im too late
2.5
0.0052
40/2
360
40 divided by 100 equals 0.4. 0.4 divided by 20 is 0.02.