Use 1/s + 1/s' = 1/f
s = 20cm
f = +10cm (positive since the mirror is concave)
1/s'=1/f - 1/s
1/s'=1/10 - 1/20 = 1/20
So, s'=20cm. The distance from the image to the mirror is 20cm, which is not surprising, since the object placed at 1/2 of the focal length and therefore exactly at the radius of curvature point. The image is real and inverted.
Real inverted and enlarged
A concave lens will appear!
It could be a triangle, a quadrilateral, a pentagon, a hexagon or even an octagon if they are two concave quadrilaterals.
Yes its like a normal mirror close up but furthur back it is upside down.
A sphere
A circle
The concave mirror focusses images to its focal point. So the images formed are real inverted and increases in size as the distance between the aperture and the object decreases. When the object is placed between the focus and the aperture the image formed is virtual erect and magnified.
A concave lens will appear!
image formed by the concave lens will be erect , virtual and smaller than the size of object.
explain the six cases for producing image formed by concave mirror
concave lens formed virtual,erect and diminished image irrespective to the distance between the object and lens.
Your right! You see technically we see up side down but with the light we see right side up so what that means is yes it is upside down. Well, since the brain doesn't turn it "right side up" it could be either way that you look at it.
vetical upright a
Real, reduced, and inverted.
Image formed by a concave lens or a diverging lens is virtual,upright and smaller than the object.It is used by short sighted people.
Yes!!! A variety of image.
Paraffin is a compound made when a candle burns
If an object at is 2.5 cm long is placed on the axis of a concave mirror that is 30 cm radius of curvature at a distance of 10 cm away from it, the position size and nature of the image formed would be 20 cm. This is a math problem.