99990 Note that if you add 11 to my answer you get a 6-digit number therefore it must be the largest 5-digit whole multiple of 11.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
The first digit can be any one of them ... 1, 2, 3, 4, 5 ... five choices. For each one . . .The second digit can be any one of them ... five choices. For each one . . .The third digit can be any one of them ... five choices. For each one . . .The fourth digit can be either 2 or 4 ... two choices.Total number of 4-digit possibilities: (5 x 5 x 5 x 2) = 250
-70
It is: 0.05 = five hundredths
When a number is a multiple of 5, the possible values of the ones digit are zero and five.
-3
If the 2 digit number is a multiple of both 5 and 7 then it is a multiple of (5 x 7) which equals 35. The only even 2 digit number which is a multiple of 35 is, 2 x 35 = 70
99990 Note that if you add 11 to my answer you get a 6-digit number therefore it must be the largest 5-digit whole multiple of 11.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
When a number is a multiple of 5, the possible values for the ones digit are zero and five.
The first digit can be any one of them ... 1, 2, 3, 4, 5 ... five choices. For each one . . .The second digit can be any one of them ... five choices. For each one . . .The third digit can be any one of them ... five choices. For each one . . .The fourth digit can be either 2 or 4 ... two choices.Total number of 4-digit possibilities: (5 x 5 x 5 x 2) = 250
No, the multiples of 5 are all of the whole numbers whose "1's" digit is either 0 or 5.
99045
-70
It is: 0.05 = five hundredths
The value of the digit 5 is 5/10. 2.5 = 2+5/10