10,000
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99990 Note that if you add 11 to my answer you get a 6-digit number therefore it must be the largest 5-digit whole multiple of 11.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
The first digit can be any one of them ... 1, 2, 3, 4, 5 ... five choices. For each one . . .The second digit can be any one of them ... five choices. For each one . . .The third digit can be any one of them ... five choices. For each one . . .The fourth digit can be either 2 or 4 ... two choices.Total number of 4-digit possibilities: (5 x 5 x 5 x 2) = 250
-70
It is: 0.05 = five hundredths