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If x ≡ 39 mod 357 then:

x = 357k + 39 for some integer k.

Now 357 = 21×17, and 39 = 2×17+5

→ x = 21×17×k + 2×17 + 5

→ x = 17(21k + 2) + 5

→ x = 17m + 5 where m = 21k + 2 (is an integer)

→ x ≡ 5 mod 17

→ the remainder when the number is divided by 17 is 5.

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8y ago

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