ds/dt gives the velocity at that instant. So slope gives the velocity
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The slope of a position vs time graph represents the velocity of the object. It indicates how the position changes over time, with a steeper slope corresponding to a higher velocity and a flatter slope corresponding to a lower velocity.
dx / dt = slope = tg(alpha) = velocity
d means 'difference between' or 'change in'
x means 'place of object'
t means 'time'
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
No, the speed of an object can be found by calculating the slope of a position-time graph. The steeper the slope, the greater the speed of the object.
It is false. The slope of a straight line on a position-time graph is the average velocity. Slope = y2-y1/x2-x1. On a position-time graph, y is the position (d), and x is the time (t). So y2-y1 = df-di = displacement, and x2-x1 = tf-ti = time interval. Average velocity = displacement/time interval = df-di/tf-ti
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
A position-time graph shows the relationship between an object's position and time. The position of the object is typically plotted on the y-axis, while time is on the x-axis. The slope of the graph represents the object's velocity, with a steeper slope indicating a higher velocity.