pr(2 then 4) = pr(2) × pr(4) = 1/10 × 1/10 = 1/100
The answer is 1/100.
1/10
It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
It is (the number of sectors which are numbered 2) divided by 6
There is a 2 in 5 chance that the spinner will stop in a red section.
9
If it is a fair spinner, then 3/8
The answer depends on how many sides the spinner has and how they are numbered. It also depends on how many time it is spun.
The probability is one in four, or 25%.
5/12 If it's wrong don't mind me, i'm not even in middle school yet i'm just smart
17 out of 21
It is 0.5
1/10
It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The probability is 3/7.
The probability is 5/9.