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Q: A squared plus b squared equals c squared?

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b = sqrt32 or 4 root 2

The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.

pythagoras

C equals the square root of 1000 or 31.622776601683793319988935444327...

you use A squared plus B squared equals C squared

Pascal

no

The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.

Pythagoras.

you mean c? haha pythagoras

Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.

(b + 2c)(b - c)

a2+b2=c2 a squared plus b squared equals c squared

The solution follows A=42 42X42=1764 B=56 56X56=3136 sum of above=4900 (70X70=4900) Given you was looking for C and not C squared. Try A and B and doublecheck it for me.

Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.

A squared plus B squared equals C squared, where C is the hypotenuse of a right triangle and A and B are the other two sides is true and is one way of expressing the Pythagorean Theorem.

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)

* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73

Pythagoras' theorem in finding the lengths of the sides of a right angled triangle.

B squared equals c squared minus a squared then to find B take the square root of you answer for b squared

yes

Not sure how to put it. The Pythagorean therom states that a squared plus b squared equals c squared. Aren't a, b and c all variables?

the answer is a

A.

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