Q: A stone is projected with a velocity of 58.8 ms at an angle of 30 degree from horizontal find the Time of flight maximum height and horizontal range?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

4

Both the arrows will cover equal horizontal distance as their angles are at an difference from 45 degree. Horizontal range is maximum at 45 degrees and decreases equally on sum or difference of an angle from 45. But vertical distance increases on addition of an angle from 45 and decreases on subtraction of angle from it. For more details, contact at saqibahmad81@yahoo.com

A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.

Ask Sir JB.

12

Related questions

Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.

body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range

The degree is equal to the maximum number of times the graph can cross a horizontal line.

At the highest point of the particle's trajectory, its kinetic energy will be zero because it momentarily comes to a stop at that point. Potential energy will be at a maximum at this point.

A 45-degree throw maximizes the horizontal distance traveled by balancing the vertical and horizontal components of the projectile's velocity. At this angle, the horizontal component is at its maximum, maximizing the range the object can travel before hitting the ground. Any angle higher or lower will result in a shorter distance traveled.

The weapon should be fired at a 45-degree angle from the horizontal to achieve the minimum distance traveled by the projectile. This angle maximizes the range (horizontal distance) of the projectile by balancing the vertical and horizontal components of its velocity. At any other angle, the total distance traveled would be greater.

The induced current is maximum when the axis of the conductor, its velocity, and the magnetic field lines are all mutually perpendicular.

The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).

As the rock rises, its horizontal component of velocity remains constant. This is because there is no horizontal force acting on the rock to change its velocity in that direction. The only force affecting the rock's motion is gravity, which acts vertically, causing its vertical component of velocity to decrease until the rock reaches its peak height and then falls back down.

The weight and shape of the bullet, the speed at which the bullet leaves the gun, and the degree of tilt of the barrel above the horizontal.

Horizontal position is strate 90 degree

4