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  1. A stone is thrown with an angle of 530 to the horizontal with an initial

velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?

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kevin1723

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3y ago

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What is maximum rang of projectile motion?

Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.


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When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.


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Why does a 45 degree throw go the furthest?

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At what angle from a horizontal should a weapon be fired to achieve minimum distance traveled by the projectile?

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A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?

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