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Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

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15y ago

Java won't solve equations for you. Do the algebra with pencil and paper; in this case, I assume you want to solve for x. Then write a command to calculate the value, and assign it to x.

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Q: Ax plus b equals 0 in java?
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Related questions

Ax plus bx plus c equals 0?

x = -c/(a+b), provided a+b is not 0


What kind of equation is ax plus b equals 0 in?

A linear equation.


What is 3x squared plus 6x-3 equals 8 in the form of Ax squared plus Bx plus C equals 0?

It is: 3x2+6x-11 = 0


What will be the X in terms of a and b if Cos aX equals 1 plus bX and a and b are constants?

a = 0, b = 0.


When Ax plus By equals C passes through the origin will C equal 0 on the graph?

Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.


What is an equation that can be expressed in the form of the equation y equals ax squared plus bx plus c where the variable 'a' is not equal to 0?

The equation ax2 + bx + c = 0, where a != 0 is called quadratic.


How are the graphs of functions defined by rules like y equals ax plus bx different from those of functions with rules like y equals ax plus c?

The graph of the first form passes through the origin while the second does not - unless c = 0.


If the graph of a linear equation Ax plus By equals C passes through the origin then will C equal 0?

Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.


What point do all the graphs of the form y equals ax where a equals 0 have in common?

If y = ax and a = 0, then y=0. No matter what x is, y is still 0. Therefore any graph of y=ax (where a=0) will simply be a line at y=0, which is the x-axis.


How do you change y equals mx plus b to Ax plus By plus C equals 0?

Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.


How do you write this equation 7x-3 equals 3 in ax plus b equals 0 form?

7x - 3 = 3 Subtract 3 from both sides: 7x - 6 = 0 So a = 7 and b = -6


If a equals positive and b equals negative and c equals zero how many solutions does a Quadratic Equation have?

Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a