Yes it can. It goes in 8 times.
Seven 8's go into 56. 56/8 = 7 because 7 x 8=56
8 = 56/7
7.
The number that both 7 and 8 can go into evenly is 56.
7 and 8 both go into 56
8 goes into 56 evenly, and the answer is 7. That means 7 X 8=56 with no remainders.
56
8 = 56 / 7
Seven can go into fifty-six a total of eight times, since (56 \div 7 = 8). This means that if you multiply 7 by 8, you get 56.
8 x 7 = 56, 7 x 3 = 21, so 7
These numbers all go into 56 evenly: 1, 2, 4, 7, 8, 14, 28, 56.
56