-1101002
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First you need enough binary to convert.
0000 1101 0011 1101
Now that we have two bytes of data, separated into groups of four, conversion is easy. Just use a table, unless you happen to have it memorized.
0D3D
106.
0 *128 = 0
1 * 64 = 64
1 * 32 = 32
0 * 16 = 0
1 * 8 = 8
0 * 4 = 0
1 * 2 = 2
0 * 1 = 0
64 + 32 + 8 + 2 = 106.
Suppose you want to add 11 and 12.instruction are : mvi a,11h mvi b ,12h mov d,b add b
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped