The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
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The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
1 yd = 3 ft ⇒ 22 ft = 22/3 yds and 3 ft = 3/3 = 1 yd 22 ft x 22 ft x 3 ft = 22/3 yd x 22/3 yd x 1 yd = 484/9 cu yds = 537/9 cu yds ≈ 53.78 cu yds
Mathematically, a yard is a measure of length, has only one dimension and thus has no volume which has three dimensions; so no matter how many of them you have you will never get a volume of 15 cu ft.If you are using "yard" in the slang, builders' way to represent cubic yards, then:1 yd = 3 ft1 cu yd = 1 yd x 1 yd x 1 yd= 3 ft x 3 ft x 3 ft= 27 cu ft⇒ 15 cu ft = 15 ÷ 27 cu yd= 5/9 cu yd≈ 0.56 cu yd
36 in = 1 yd3 ft = 1 yd1 sq yd = 1 yd x 1 yd= 3 ft x 3 ft= 9 sq ft→ 256 sq ft x 2 in = (256 ÷ 9) sq yds x (2 ÷ 36) yds= 128/81 cu yds= 147/81 cu yds≈ 1.58 cu yds.
1 yd = 3 ft → 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 ft 1 yd = 36 in → volume = 4800 sq ft x 5 in = 4800 ÷ 9 sq yd x 5 ÷ 36 yd = 74 2/27 cu yd ≈ 74.074 cu yd.
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal