The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
The result depends which of the two is the diameter, and which is the height. The formula is pi x radius2 x height, where radius is half the diameter.
1 yd = 3 ft ⇒ 22 ft = 22/3 yds and 3 ft = 3/3 = 1 yd 22 ft x 22 ft x 3 ft = 22/3 yd x 22/3 yd x 1 yd = 484/9 cu yds = 537/9 cu yds ≈ 53.78 cu yds
Mathematically, a yard is a measure of length, has only one dimension and thus has no volume which has three dimensions; so no matter how many of them you have you will never get a volume of 15 cu ft.If you are using "yard" in the slang, builders' way to represent cubic yards, then:1 yd = 3 ft1 cu yd = 1 yd x 1 yd x 1 yd= 3 ft x 3 ft x 3 ft= 27 cu ft⇒ 15 cu ft = 15 ÷ 27 cu yd= 5/9 cu yd≈ 0.56 cu yd
36 in = 1 yd3 ft = 1 yd1 sq yd = 1 yd x 1 yd= 3 ft x 3 ft= 9 sq ft→ 256 sq ft x 2 in = (256 ÷ 9) sq yds x (2 ÷ 36) yds= 128/81 cu yds= 147/81 cu yds≈ 1.58 cu yds.
1 yd = 3 ft → 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 ft 1 yd = 36 in → volume = 4800 sq ft x 5 in = 4800 ÷ 9 sq yd x 5 ÷ 36 yd = 74 2/27 cu yd ≈ 74.074 cu yd.
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
27 1 cu ft bags or 9 3 cu ft bags.
1 yd = 3 ft ⇒ 22 ft = 22/3 yds and 3 ft = 3/3 = 1 yd 22 ft x 22 ft x 3 ft = 22/3 yd x 22/3 yd x 1 yd = 484/9 cu yds = 537/9 cu yds ≈ 53.78 cu yds
9
Mathematically, a yard is a measure of length, has only one dimension and thus has no volume which has three dimensions; so no matter how many of them you have you will never get a volume of 15 cu ft.If you are using "yard" in the slang, builders' way to represent cubic yards, then:1 yd = 3 ft1 cu yd = 1 yd x 1 yd x 1 yd= 3 ft x 3 ft x 3 ft= 27 cu ft⇒ 15 cu ft = 15 ÷ 27 cu yd= 5/9 cu yd≈ 0.56 cu yd
3.14r2h=V 3.14(122)(9)=4071.5 ft^3
3 baloons per 9 sq ft
Assuming you mean the colloquial (builder's) yard for cubic yard: 36 in = 1 yd 3 ft = 1 yd ⇒ 3 ft x 3 ft = 1 yd x 1 yd ⇒ 9 sq ft = 1 sq yd ⇒ 4500 sq ft x 1 in = (4500 ÷ 9) sq yd x (1 ÷ 36) yd = 138/9 cu yd ≈ 13.89 cu yd
36 in = 1 yd3 ft = 1 yd1 sq yd = 1 yd x 1 yd= 3 ft x 3 ft= 9 sq ft→ 256 sq ft x 2 in = (256 ÷ 9) sq yds x (2 ÷ 36) yds= 128/81 cu yds= 147/81 cu yds≈ 1.58 cu yds.
1 yd = 3 ft → 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 ft 1 yd = 36 in → volume = 4800 sq ft x 5 in = 4800 ÷ 9 sq yd x 5 ÷ 36 yd = 74 2/27 cu yd ≈ 74.074 cu yd.
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
Assuming you're using the colloquial "yard" for the "cubic yard" unit of volume and not the "yard" unit of length:3 ft = 1 yd36 in = 1 ydvolume = 24 ft x 12 ft x 4 in= (24/3) yd x (12/3) yd x (4/36) yd= 32/9 cu yd= 35/9 cu yd≈ 3.56 cu yd
9 cubic feet per per cubic yard