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What is the solution is the of this equation root 7- 1 divide by root 7 plus 1 - root 7 plus 1 divide by root 7 - 1?
It will depend on where you put your parentheses. Root 7 -( 1/root 7) is different from (root 7-1)/root 7. * * * * * True, but a more helpful answer: [sqrt(7) - 1]/[sqrt(7) + 1] - [sqrt(7) + 1]/[sqrt(7) - 1] Multiplying the numerator and denominator of the first fraction by [sqrt(7) - 1] and the second fraction by [sqrt(7) + 1] = [sqrt(7) - 1]2/[7 - 1] - [sqrt(7) + 1]2/[7 - 1] =[7 - 2*sqrt(7) + 1]/6 - [7 + 2*sqrt(7) + 1]/6 = 16/6 = 8/3
What is the prime factorization of the square root of 441?
√441 = √(3^2 × 7^2) = 3 × 7.
What is seven divide two thirds?
7 divided by 2/3 = 7 x 3/2 = 21/2
What is the distance between two points -2 7 and 3 7?
(-2-3)2+(7-7)2 = 25 and the square root of this is the distance which is 5
How do you factor 7x2 - 12 equals 0?
It doesn't factor neatly. If you solve it, you get the square root of 12/7 which is either 2 times the square root of 3/7 or -2 times the square root of 3/7
