No, just one.
To determine the number of significant figures in the answer to the calculation 65.25 m x 37.4 m, we look at the significant figures of each number. The number 65.25 m has four significant figures, while 37.4 m has three significant figures. The result should be reported with the least number of significant figures, which is three in this case. Therefore, the answer will have three significant figures.
Three. The trailing zero IS significant.
Three significant figures: two before the decimal point and one after.
Three as three is the minimum found
2300.m has four significant figures.
To determine the number of significant figures in the answer to the calculation 65.25 m x 37.4 m, we look at the significant figures of each number. The number 65.25 m has four significant figures, while 37.4 m has three significant figures. The result should be reported with the least number of significant figures, which is three in this case. Therefore, the answer will have three significant figures.
There are three significant figures in 4.00
Three. The trailing zero IS significant.
Three significant figures: two before the decimal point and one after.
Three as three is the minimum found
Three, four, five or six
2300.m has four significant figures.
125 m in two significant figures is: 120 m
6.07 m Has three significant figures because the 0 is between two whole numbers and thus holds a place.
2 significant figures.
To find the product of 3.15 m and 2 m, you multiply the two values: (3.15 \times 2 = 6.30) m². However, the number of significant figures must be considered. The value 3.15 has three significant figures, while 2 has one significant figure. Therefore, the result should be reported with one significant figure, which gives a final answer of 6 m².
Six significant figures.