Not 49, but 36/3=12
3 with 29 remaining 176 - 29 = 147 = 49 x 3
3, 7, 21, 49
The divisors of 147 are 1, 3, 7, 21, 49, and 147.These do: 1, 3, 7, 21, 49, 147.
Exactly, 5x 8 + 3x 3
No, 3 cannot go into 49 evenly because 49 is not divisible by 3 without leaving a remainder.
Not 49, but 36/3=12
49, because 147/3=49
49 does not go into 189 evenly. 189 divided by 49 equals 3 with a remainder of 42.
3 with 29 remaining 176 - 29 = 147 = 49 x 3
Yes, but not evenly.
49
16
3, 7, 21, 49
49 divided by 16 is 3 with remainder 1.
3 with remainder 1.
1, 2, 3, 6, 9, 18 1, 7, 49