Yes, you can and it becomes:(x+10)(x-10)
You factor out 5 from the expression (10+5p). You get 2(5+p).
p2-5p-50= (p-10) (p+5)
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This does not factor over the field of rational numbers. If does factor over the reals. Use the quadratic formula to find the roots for the related quadratic equation: x2-11x-10 = 0 Cal them r1 and r2. The factors are (x - r1) and (x - r2.)
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If you mean: 2x+10 then it is 2(x+5)
Yes, you can and it becomes:(x+10)(x-10)
Please help, math problems. 8p - 10 of 5 + x = ...??
You factor out 5 from the expression (10+5p). You get 2(5+p).
p2-5p-50= (p-10) (p+5)
x^2 - 10 x + 25 = (x - 5)(x - 5)
x^2+7x-30 = (x-3)(x+10)
8x2 - 10x - 3 = (2x - 3)(4x + 1)
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if you want to factorise it then it will become (2x + 5)(x + 2) if it was equal to something then you would work it out differently. hope this helps