It is (x-3)(x-4) when factored
You find two numbers whose sum is -7 and product is +10. x2 - 7x + 10 = (x - 2)*(x - 5)
(2x + 1)(3x - 5)
It is: x(x+7) when factorized
7x+10=31x so 10=31x-7x or 10 =24x in which case x=10/24 or 5/12
It is (x-3)(x-4) when factored
x2+7x+12=0usually this means to factor the equation.factored this equation would be...(x+3)(x+4)
You find two numbers whose sum is -7 and product is +10. x2 - 7x + 10 = (x - 2)*(x - 5)
(2x + 1)(3x - 5)
It is: x(x+7) when factorized
Factorizing 7x-35 gives 7 (x - 5).Factorizing is to express a number or expression as a product of factors.When factorizing always look for common factors. To factorize (7x-35) look for the highest factor between the two terms (7). 7x - 35 = 7 (x - 5)
7x+10=31x so 10=31x-7x or 10 =24x in which case x=10/24 or 5/12
7x2+49x+84 = 0 Divide all terms by 7: x2+7x+12 = 0 Factorize: (x+3)(x+4) = 0 Therefore the x intercepts are -3 and -4
x2 - 7x + 10 = 28; whence, x2 - 7x - 18 = 0, and (x - 9)(x + 2) = 0. The above is true exactly when, either, x - 9 = 0, or x + 2 = 0. Therefore, the solution is: x = 9 or -2. Checking, 92 - (7)(9) + 10 = 81 - 63 + 10 = 28; and (-2)2 - (7)(-2) + 10 = 4 + 14 + 10 = 28; verifying the solution found above.
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To factorize the quadratic expression x^2 + 7x + 12, we need to determine two numbers that multiply to give us 12 and add up to 7. In this case, the numbers are 3 and 4. Therefore, the factored form of the expression is (x + 3)(x + 4).
7x=20+20x collect terms containg x on one side and then factorize -13x=20 0r, x=-20/13