ell t y
NULL VECTOR::::null vector is avector of zero magnitude and arbitrary direction the sum of a vector and its negative vector is a null vector...
The sum of two null vectors is a null vector. And since a direction is not relevant for a null vector, the resultant has no direction either.
A: Practically all of the bridges used to find the value of passive components uses a null signal to determine the value In reality null means the lack of a signal where it is virtually eliminated when that occurs that is the null or no signal.
A user guide on networking with a null modem can be found in various places. One place is to check the information that came with the null modem. If one cannot find the answers they seek there, then another place is to check with a networking expert.
You mean SQL? NULL = anything IS NULL NULL <> anything IS NULL ... NULL IS NULL = TRUE NULL IS NOT NULL = FALSE
To find the sum of something means to add. Example: 9X3=27 The sum of 9x3 is 27.
The sum of three whole odd numbers will always be odd keeping in mind that zero is neither even nor odd and that 'null' is not a number.
You can find a Null Modem Serial Cable for sale from stores such as Walmart, Tiger Direct and Radio Shack. You can also get these cables from retailers such as Amazon.
adding numbers together has the answer to the sum.
There is no null, it is just what it says when you log out. There is a null.
You find the sum of two numbers by adding the two together. Example: The sum of 1 + 1 is 2
void del(int item) { node *parent,*location; if(root==NULL) { cout<<"Tree empty"); return; } find(item,&parent,&location); if(location==NULL) { cout<<"Item not present in tree"; return; } if(location->lchild==NULL && location->rchild==NULL) case_a(parent,location); if(location->lchild!=NULL && location->rchild==NULL) case_b(parent,location); if(location->lchild==NULL && location->rchild!=NULL) case_b(parent,location); if(location->lchild!=NULL && location->rchild!=NULL) case_c(parent,location); free(location); }/*End of del()*/ void find(int item,node **par,node **loc) { node *ptr,*ptrsave; if(root==NULL) /*tree empty*/ { *loc=NULL; *par=NULL; return; } if(item==root->info) /*item is at root*/ { *loc=root; *par=NULL; return; } /*Initialize ptr and ptrsave*/ if(item<root->info) ptr=root->lchild; else ptr=root->rchild; ptrsave=root; while(ptr!=NULL) { if(item==ptr->info) { *loc=ptr; *par=ptrsave; return; } ptrsave=ptr; if(item<ptr->info) ptr=ptr->lchild; else ptr=ptr->rchild; }/*End of while */ *loc=NULL; /*item not found*/ *par=ptrsave; }/*End of find()*/