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It's a bit hard to explain in words. Suppose you have four congruent isosceles triangles: ABC, DEF, GHI, and JKL. (the vertexes are A, D, G and J). Place DEF and ABC so that the bases are touching. You now have quadrilateral ABDC ( when 2 points coincide, use the letter which comes first in the alphabet).

Place GHI so that G is at B and H is at A. You now have quadrilateral AIDC (IBD is a straight line).

Place JKL so that L is at D and J is at B. Now AIBKDC is the concave hexagon.


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How do you make a concave hexagon from four triangle?

You start creating a concave hexagon from four triangles by placing the smallest triangle in the middle to serve as a base for the other three. Line up the bases on each triangle with the sides of the smallest one to end up with six sides forming a concave hexagon.


How do you make a concave hexagon from 4 triangles?

Put four equilateral triangles so that each one of them has a vertex at a single point and the triangles abut one another. The shape will be 4/6 (= 2/3) of a regular hexagon.


How do you make 4 triangles into a concave hexagon?

To form a concave hexagon from four triangles, you can arrange the triangles such that two of them share a common side, while the other two are positioned to create indentations. For example, place two triangles adjacent to each other to form a larger triangle, then attach the third triangle to one side, and the fourth triangle in a way that creates an inward point, forming a concave shape. Make sure that the angles of the triangles allow for the necessary concave indentations, resulting in a six-sided figure with at least one inward angle.


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How do you make a irregular hexagon out of 6 equilateral triangles?

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