Place GHI so that G is at B and H is at A. You now have quadrilateral AIDC (IBD is a straight line).
Place JKL so that L is at D and J is at B. Now AIBKDC is the concave hexagon.
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You need at least four triangles, or at least three trapeziums. Or two triangles and one trapezium.
First make a regular hexagon. Then take any one triangle and slide it through two heights so that it's base is on what was the opposite side. You will have an irregular, concave hexagon, shaped somewhat like an arrowhead.
6 polygon triangles make a hexagon
No?
How can a you make a hexagon using a trapozid and 2 triangles