The area of ANY triangle is base x height. The height must be measured perpendicular to the base.
In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
How do you figure out the figure is formed by a square and an isosceles trapezoid what is the area of the figure 7 in wide by 5 inches by 5 inch by 5.5
The formula is: Base times Height divide by two.
All triangles have a total of 180 degrees. In an isosceles triangle the two angles opposite the side of equal length will have equal degrees.
For all triangles: area = 1/2 * base * height
For all triangles: area = 1/2 * base * height
You cannot since there is not sufficient information.
To find the area of any triangle... divide the length of the base by 2... then multiply the result by the height.
Yes. You would have to have a right angle and two 45 degree angles
The three inside angles of any tringle always add up to 180 degrees.
The formula is: Base times Height divide by two.
All triangles have a total of 180 degrees. In an isosceles triangle the two angles opposite the side of equal length will have equal degrees.
(1/2) * base * height
1/2(BASExHEIGHT)
For all triangles: area = 1/2 * base * height
i is usually 1/3 of the area but if you want to find the area off a certain
You can't. It is impossible.
Area = 1/2*(sum of the 2 parallel sides)*height
For all triangles: area = 1/2 * base * height