0
Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.
To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.
Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is
49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.
Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.
To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.
Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is
49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.
Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.
To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.
Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is
49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.
Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.
To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.
Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is
49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.
Still curious? Ask our experts.
Chat with our AI personalities
Ross
Taiga
RafaCalculate the number of possible combinations. The probability of winning is the reciprocal of that number.
To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.
Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is
49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.
Add your answer:
Earn +20 pts
What is the probability of winning the jackpot if you play the Florida lotto?
I bet that you will find it printed on the back of any Florida Lotto ticket.
What are the chances of winning the lottery?
You have a better chance of getting struck by lightning than winning the lottery which is 1:10,000,000.The chances of winning the lottery are very slim. You have a chance that is so small its not worth it.
A team has the probability of winning one out of every six games What is the minimum number of games the team should play to have a fair chance of winning atleast one game?
A fair chance of winning is more than 50% chance of winning. Therefore probability = 0.5 We need to find a fair chance of winning atleast one match. 1-(5/6)^n > 0.5 hence, n=4 QED (quite easily done, :-p)
When calculating the probability of a single trial experiment with a compound event why is it necessary to subtract?
Well, honey, when dealing with compound events, you gotta subtract the probability of the event not happening from 1 to get the probability of it happening. It's like making sure you cover all your bases - can't have any sneaky probabilities slipping through the cracks. So, subtracting is just a fancy way of making sure you've accounted for all the possibilities.
How to find Median of probability distribution?
how do i find the median of a continuous probability distribution
