-99
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The answer is 5050.
One way to see how to get the answer is as follows:
Suppose
S = 1 + 2 + 3 + . . . + 100
Then, rewriting it another way,
S = 100 + 99 + 98 + . . . + 1
Now the sum of each number and the one below it is 101 and there are 100 such pairs.
So
2*S = 101 + 101 + 101 + . . . + 101 (100 entries)
2*S = 100*(100+1)
So S = 100*(100+1)/2 = 50*101 = 5050
1000, 1020, 1040, 1060, 1080, and 1100
Mean average of 175, 550, 750 & 1100 (175+550+750+1100)/4 = 643.75
0.001, 1.1, 10, 100, 1100, 10000100
-1097
1111 is the only one.