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I will assume the "7..." continues. There is some shortcut which I don't remember; the reasoning - and the calculations you can do - are as follows.Since there is ONE repeating digit, you use a factor of 10 for the following. (For two repeating digits, as in 0.5131313..., you would use a factor of 100; for three repeating digits, you use a factor of 1000, etc.).

Call your number "x":

x = 0.377777... (equation 1)

Multiply it by 10:

10x = 3.77777... (equation 2)

Subtract equation 1 from equation 2, and solve for "x".


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8y ago
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8y ago

Let x = 0.37777

10x = 3.7777

100x = 37.7777

Subtract the second from the third.

90x = 34

x = 34/90 or 17/45

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