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The convention is that when you just write "mol" or "mole" you are referring to gmol so the conversion is to just replace gmol with mol.
In chemical engineering where the quantities of material being processed may be on the scale of tons, other "mole" related units are defined such as kg-mol and ton-mol.
As examples:
Since the molecular weight of a diatomic molecule of oxygen is 31.9988,
31.9988 g of oxygen gas = 1 g-mol
31.9988 lb of oxygen gas = 1 lb-mole
31.9988 kg of oxygen gas = 1 kg-mole
31.9988 tons of oxygen gas = 1 ton-mole.
These units make stoiciometric calculations convenient for designing industrial processes.
First, you need to know the Molar Mass of the substance, then you divide the g dm-3 (i.e. concentration) by the Molar Mass.
Explaination:
The concentration is in the units of g / dm3
The Molar Mass of the substance is in the units of g / mol
When you divide the concentration by the Molar Mass you get:
(g / dm3) / (g / mol )
The "g"s cancels out and we are left with mol dm-3
i.e. g dm-3 * g-1 mol = mol dm-3
6.17 x 10-3 mol dm-3
16.74/ 10^6 =1.674 * 10^5 dm^3
answer is 2.4 x 10v-3
0.254 dm = 1 in (exactly) → 1 dm = 1 ÷ 0.254 in → 1 dm^3 = 1 dm x 1 dm x 1 dm = (1 ÷ 0.254 in) x (1 ÷ 0.254 in) x (1 ÷ 0.254 in) = 1 ÷ (0.254^3) cu in → 15615 dm^3 = 15615 ÷ (0.254^3) cu in ≈ 952886 cu in
grams of solute per 100 milliliters of solution
dm3=1m2
6.17 x 10-3 mol dm-3
16.74/ 10^6 =1.674 * 10^5 dm^3
It is supposed to be mol/dm-3 Actually, 1 dm cube is the same as 1 litre. Therefore, there is no need of conversion. Both are the same.
It is supposed to be mol/dm-3 Actually, 1 dm cube is the same as 1 litre. Therefore, there is no need of conversion. Both are the same.
1 metre3 = (10 dm)3 = 1000 dm3So 500 dm3 = 0.5 m31 metre3 = (10 dm)3 = 1000 dm3So 500 dm3 = 0.5 m31 metre3 = (10 dm)3 = 1000 dm3So 500 dm3 = 0.5 m31 metre3 = (10 dm)3 = 1000 dm3So 500 dm3 = 0.5 m3
Since, 10 cm = 1 dm , 10 cm x 10 cm x 10 cm = 1 dm x 1 dm x 1 dm , Then, 1000 cm^3 = 1 dm^3
A liter is equal to a dm3. So, we have 3,292 dm3 solution. We need the amount of the NaCl. It is m/M -> 17,62 / 58,5 -> approx. 0,3012 mol. So, the molarity is 0,3012 / 3,292 -> 0,0915 mol dm-3 .
10^-6 or one millionths of a dm^3 is one mm^3.
pH 10 means [H+] = 1x10^(-10) mol dm-3 (0.0000000001 mol dm-3) pH 8 means [H+] = 1x10^(-8) mol dm-3 (0.00000001 mol dm-3) So basically it's changed by a factor of 100.
One decimetre cubed is equivalent to one litre.
98 g per dm3 would be 1 molar - so 49 g would be 0.5 molar , so 4.9 g is 0.05 mol per dm3 or 0.05 mol.dm-3