You cannot. A hexagon has 9 diagonals.
You cannot. A hexagon has 9 diagonals.
You cannot. A hexagon has 9 diagonals.
You cannot. A hexagon has 9 diagonals.
Diagonals in an hexagon: 0.5*(6^2 -3*6) = 9 diagonals
There are 2
A hexagon has more than 2 diagonals. -♥Paulina
In a regular hexagon in which the angles are congruent you can use a formula. ((6-2)*180)/6 120 degrees. The reason this works is that you can draw 4 diagonals inside the hexagon and triangles have 180 degrees each.
Use the formula: 0.5*(n^2 -3n) = sum of diagonals whereas 'n' is number of sides So: 0.5*(36-18) = 9 diagonals in a 6 sided hexagon
Diagonals in an hexagon: 0.5*(6^2 -3*6) = 9 diagonals
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
There are 2
A hexagon has more than 2 diagonals. -♥Paulina
In a regular hexagon in which the angles are congruent you can use a formula. ((6-2)*180)/6 120 degrees. The reason this works is that you can draw 4 diagonals inside the hexagon and triangles have 180 degrees each.
Hexagon: 6*(6-3)/2 = 9Heptagon: 7*(7-3)/2 = 14
Use the formula: 0.5*(n^2 -3n) = sum of diagonals whereas 'n' is number of sides So: 0.5*(36-18) = 9 diagonals in a 6 sided hexagon
4 diagonal 2 straight 6 alltogether * * * * * Unfortunately, not true. A hexagon has 9 diagonals. A polygon with n vertices has 1/2*n*(n - 3) diagonals.
A shape with five diagonals is a hexagon. A hexagon has six sides, and the formula for calculating the number of diagonals in a polygon is given by ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a hexagon, substituting ( n = 6 ) results in ( \frac{6(6-3)}{2} = 9 ) diagonals. Therefore, a shape that specifically has five diagonals is a pentagon, as it fits the formula with ( n = 5 ): ( \frac{5(5-3)}{2} = 5 ).
you can make 2 trapezoids
Yes