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Q: How do you evaluate 4a plus 7c and A equals 5 C equals 3?

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4a+3b can not be algebraically simplified. It can be evaluated if you assign values to a and b.

c = 3

No

7C MINUS bracket open c plus 2 bracket close equals 7c minus c minus 2 equals 6c minus 2

12a + 6b + 6c = 6(2a + b + c)

Gathering like terms together, this is equal to 5a + 3b + 7c.

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Get two slaves. Give one equation to each slave. Say, "Go!"

12c + 2b

It equals 10c+2 because you have to combine like terms when you use variables. So since there is a 7c and a 3c you add those because it says plus add you end up with 10c+2 because you are still adding the 2.

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