m^2 + 12m - 28 = (m + 14)(m - 2)
The other factor is 1.
Factor 2x plus 12x plus 28 is (x - 3)(x - 9)
a + b + 4 is in its simplest form.
x2 + 5x + not really sure what that extra plus is for... this is the most you can factor it... x(x + 5)
(m + 9)(m + 9)
m2 + 9m + 20 = (m + 5) (m + 4)
(m - 3n)(m + 3n - 2)
(m - 3n)(m + 3n - 2)
m^2 + 12m - 28 = (m + 14)(m - 2)
The GCF of m2, m3, and m4 is m2.
it because m2 plus ions have two valence electrons in two shells instead of one
m2+m-90 = (m-9)(m+10) when factored
11
No.
That depends on the value you give to 'm'.
(m - 2)(m - 10)