4n3 - 12n2 - 7n + 9
15n + 5 or 5(3n + 1)
7n(n−1)
I don't know, just please helpp!
n(2n - 1)(2n + 7)
m(12 + 7n)
22n + 2.
6m + 5n - 4m + 7n = 2m + 12n
Gather like terms. The - 2 and 4; the 7n and 3n. 7n - 2 + 3n + 4 = 10n + 2
7n - 2 + 3n + 4 = 7n + 3n - 2 + 4 = 10n + 2 which can be simplified to 2(5n +1)
-7n2 + 74n + 33 = -7n2 + 77n - 3n + 33 = -7n*(n - 11) - 3*(n - 11) = =(-7n - 3)*(n - 11) = -(7n +3)*(n - 11)
This question as written can be taken two ways: 9m + 6n - 3m + 7n = 6m + 13n, or (9m + 6n) - (3m + 7n) = 9m + 6n - 3m - 7n = 6m - n
10n + 3 = 7n + 53n = 2n = 2/3
7n + 1 = 6n + 8 7n=6n+7 (minus 1 from each side) n=7 (7n-6n equals n, you are left with n=7)
(10, 2)
Yes.
9n-2=7n+50 7n+9n=50+2 16n=52 n= 3.25