You cannot.
pi is an irrational number and the concept of factors really applies only to integers. Once you allow rationals and irrationals, every non-zero number is a factor of every other number.
You can divide pi by 4: use a calculator.
64The formula to find the volume of a sphere is4/3 * pi * r3where r is the radius of the sphere. So if the radius is increased by a factor of 4, then the formula becomes4/3 * pi * (4r)3 = 4/3 * pi * 64r3showing that the volume increases by a factor of 64.
The formula for volume of a sphere is (4/3)(pi)r3, where r is the radius. The initial volume of the sphere is then (4/3)(pi)(1)3 and the final volume is (4/3)(pi)(10)3. (Remember that we are given diameters, and need to divide them by two to find the radii to plug into the equations.)The factor by which the volume changes is (Final Volume)/(Initial Volume), which is this case is[ (4/3)(pi)(10)3 ] / [ (4/3)(pi)(1)3 ](4/3)pi cancels out, leaving 103 / 13 = 1000.
pi-4 is the opposite and 1/4-pi is the reciprocal
22 over 7
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4
Entire surface area = (2*pi*4)+(4*pi*height) = 312 (4*pi*height) = 312-(2*pi*4) (4*pi*height) = 286.8672588 Divide both sides by 4*pi to find the height:- height = 22,82817112 inches Check: (2*pi*4)+(4*pi*22.82817112) = 312 square inches Formula: (2*pi*radius2)+(diameter*pi*height) = area
cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2
Area = (Pi/4)*(dia2) = (Pi/4)*22 = (Pi/4)*4 = Pi sq.in = 3.1416 square inches.
The four roots are cos(theta)+i*sin(theta) where theta = pi/4, 3*pi/4, 5*pi/4 and 7*pi/4.
4-(4/3)+(4/5)-(4/7)+(4/9)-(4/11)....=pi There are no non-infinite serieses known for finding pi
tangent of pi/4 = 1
4 πr2π is pi... Also it is 4(pi(r^2))