(x+5)(x+3)
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)
I assume you mean...., 8X + 16 8(X + 2) ======
3x2 - 8x = x(3x - 8)
8x + 20 = 4 (2x + 5)
(x+5)(x+3)
You don't. There is no way to factorise it.
j
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Doesn't factorise in integers. Roots are 0.84 and 7.16
Use www.wolframalpha.com Enter factor 4x^2+8x-5 to receive the answer (2x-1)(2x+5)
I assume you mean...., 8X + 16 8(X + 2) ======
3x2 - 8x = x(3x - 8)
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
8x -12 ... 4(2x -3)
4x2+8x+3 ------> (2x+3)(2x+1)