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Every side (and the one opposite it) form a pair of rectangular bases.
Every side (and the one opposite it) form a pair of rectangular bases.
Every side (and the one opposite it) form a pair of rectangular bases.
Every side (and the one opposite it) form a pair of rectangular bases.
What else can I help you with?
How do you find the answer of the base area of a rectangular prism?
The base of a rectangular prism is a rectangle. The area of a rectangle is length times width.
What is the base of a rectangular prism?
The base of a rectangular prism is a base of a rectangle!
How are a triangular prism and a rectangular prism are they different?
a triangular prism is different from a rectangular prism because: their names are different a triangular prism has a triangle for its' base a rectangular prism has a rectangle base a triangular prism has less sides than a rectangular prism a rectangular prism has more sides than a triangular prism
How do you find the volume of a rectangular prism if you know the area and height?
Volume of rectangular prism = area of base x height
How do you find volume of a rectangular prism?
base times height
How do you find the perimeter of a base of a rectangular prism?
12 the base times the height
How do you find perimeter of the base of a rectangular prism?
12 the base times the height
How do you find volume of rectangular if you know base and height?
The volume of a rectangular prism is base*height*length in cubic units
Volume of trapezoidal prism?
To find the volume of a rectangular prism, multiply the base, width, and height. If the prism is irregularly shaped, multiply the base and the height.
How do you find the height of a rectangular prism if you know the volume and base?
divide them
How do you find base area of rectangular prism if you know volume and height?
Volume of a rectangular prism = base x height. If volume and height are known, solve for base area by dividing volume by height.
How do you find the volume of a rectangular prism with a square base?
Multiply base area x height.
