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Q: How do you find five consecutive number whose sum is 465?

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8,9,10,11,12

25. The middle number of the five is 105/5 = 21. The rest are 21-4, 21-2, 21+2, 21+4

They are 13, 15, 17, 19 and 21.

The numbers are 17, 18, 19, 20 and 21.

275, 277, 279, 281 and 283.

Find the greatest product of five consecutive digits in the 1000-digit number.7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450

8 10 12 14 16

Most people refer five consecutive strikes as a five bagger.

The only number that equals 995 is 995.

There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?

9 11 13 15 17

695

720.

5, 6, 7, 8, 9

Wrestling, he won five consecutive titles. Wrestling, he won five consecutive titles.

Five more than twice a number is -13 find the number

7, 8, 9, 10 and 11 The middle one must be 1/5 of your target. Then two numbers on either side of that middle number complete the required set.

60, 62, 64, 66, 68

15,17,19,21,23

You have five numbers that add up to 115. What is the average value of those five numbers? Now, how do you choose five consecutive numbers that have that average value?

Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.

741,743,745,747,749

no

you can take it as much as you want, but in a consecutive twelve months, the max time is five.

The smallest example of such a situation is: 3*7*11*13*37=111111