The problem statement with some interpretation and equation rearrangement should give y = f(x ); where, y is the dependent variable and x is the independent variable.
You might have an equation like : y = mx + b . In this situation, m is the slope and b is the y-axis intercept.
More complicated situations may require evaluation dy/dx , which is the slope.
Divide the original circle's area by the factor you want to divide it into.
Point-slope formy - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1Solution:y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x - 6 + 1y = 6x - 5
an equal sign and an answer
Point-slope form: y - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1y - y1 = m(x - x1)y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x -6 + 1y = 6x -5
To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.
the number that is shown the most in the eqution
Points: (-3, 5) and (-2, -6) Slope: -11 Straight line eqution: y = -11x-28
Divide the original circle's area by the factor you want to divide it into.
Point-slope formy - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1Solution:y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x - 6 + 1y = 6x - 5
an equal sign and an answer
The slope can be a fraction.
chemical eqution is the practical equation with chemicals chemical eqution is the practical equation with chemicals
You find the tangent to the curve at the point of interest and then find the slope of the tangent.
You find the slope of the tangent to the curve at the point of interest.
Point-slope form: y - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1y - y1 = m(x - x1)y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x -6 + 1y = 6x -5
Why do we need to find the slope of a line? The slope of a line tells us how something changes over time. If we find the slope we can find the rate of change over that period.Why do we need to find the slope of a line?The slope of a line tells us how something changes over time. If we find the slope we can find the rate of change over that period. - See more at: http://www.algebra-class.com/rate-of-change.html#sthash.KmE8ACMR.dpuf
When you are left with a number = a variable.