The problem statement with some interpretation and equation rearrangement should give y = f(x ); where, y is the dependent variable and x is the independent variable.
You might have an equation like : y = mx + b . In this situation, m is the slope and b is the y-axis intercept.
More complicated situations may require evaluation dy/dx , which is the slope.
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I'll assume that the horizontal variable is "x", and the vertical variable is "y". Usually you would solve for "y", and then take the derivative of the resulting function. There are many special cases you need to consider; read an introductory book on calculus for more details on derivatives. Usually you can use some formula, which you can look up.
If it is a linear equation of standard form y =mx + b then slope is m. If it is non linear you need to know calculus and take first derivative which is slope at any point x
Divide the original circle's area by the factor you want to divide it into.
Point-slope formy - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1Solution:y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x - 6 + 1y = 6x - 5
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Point-slope form: y - y1 = m(x - x1)m = slope = 6x1 = 1y1 = 1y - y1 = m(x - x1)y - 1 = 6(x - 1)y - 1 = 6x - 6y - 1 + 1 = 6x -6 + 1y = 6x -5
To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.