Suppose the diameter of the disk is D cm so that the radius is D/2 = R cm.
Suppose the diameter of the hole is d cm so that its radius is d/2 = r cm.
Then the area of one side of te disc is
pi*(R^2 - r^2)
Therefore the total area of the two sides is 2*pi*(R^2 - r^2) square cm.
This ignores the surface area of the edge which, although small, is not 0.
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You measure its outer diameter, divide by 2 to give the outer radius = R units.You measure its inner diameter, divide by 2 to give the inner radius = r units [radius of the hole].
Then area of the annulus = pi*(R^2 - r^2) square units.
Area of disc: pi*6^2 = 36*pi square cm
A = pi * r^2 A = pi * 6^2 A = 36pi If you are using 3.14 for pi, then ANS : D.) 113.04 cm^2
The weight of a compact disc is approx 1.6 Newtons.
175 cm
A standard compact disc is 120 millimeters in diameter (or approximately 4.72 inches).