0
Yes.
fx=5x1 / 9
Perhaps, using the Quadratic Equation...y=x2+5x-6Solve for x:x2+5x+(-6-y)=0Using the Quadratic Equation:x = .5 *(-5 (+-) (25 + (24+4y)).5) = -2.5 (+-) .5*(49+4y).5Substitute y for x, x for y:y = -2.5 (+-) .5*(49+4x).5
(x-3)(x-2)
ex and ln(x) are inverse functions. With this you can get 5x = eln(5^x) Therefore you can anti-differentiate this to get eln(5^x)/(ln(5x)) Which equals 5x/ln(5x)
No, f(x) is not the inverse of f(x).
29
17
Yes.
The discriminant is 121.
fx=5x1 / 9
Perhaps, using the Quadratic Equation...y=x2+5x-6Solve for x:x2+5x+(-6-y)=0Using the Quadratic Equation:x = .5 *(-5 (+-) (25 + (24+4y)).5) = -2.5 (+-) .5*(49+4y).5Substitute y for x, x for y:y = -2.5 (+-) .5*(49+4x).5
x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5
(x-3)(x-2)
ex and ln(x) are inverse functions. With this you can get 5x = eln(5^x) Therefore you can anti-differentiate this to get eln(5^x)/(ln(5x)) Which equals 5x/ln(5x)
(5x)2 = 25x2.
It is a quadratic equation in the variable x.