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Both sides of a square - indeed, all four sides - MUST be the same otherwise it is not a square. If the side length is s cm the area is s*s = s2 cm2
The area of a rectangle = length x width = 5 x 8 = 40 square inches.
That is the total weight of the dumbbell.
If you know the circle's area then the radius can be found: pi*radius2 = area Divide both sides by pi: radius2 = area/pi Square root both sides: radius = the square root of (area/pi)
Since the area equals pi times the square of the radius, the radius must be the square root of (the area divided by pi). I got that by dividing both sides of the equation by pi then taking the square root of both sides.
1/2*(sum of both parallel bases)*height = area multiply both sides by 2 and then divide both sides by (sum of both parallel bases) height = (2*area) divided by (sum of both parallel sides)
Both sides of a square - indeed, all four sides - MUST be the same otherwise it is not a square. If the side length is s cm the area is s*s = s2 cm2
The area of a rectangle = length x width = 5 x 8 = 40 square inches.
That is the total weight of the dumbbell.
The question is a bit vague to follow but in general the area of a trapezoid is 0.5*(sum of parallel sides)*height and the area of a square is a side squared.
If you know the circle's area then the radius can be found: pi*radius2 = area Divide both sides by pi: radius2 = area/pi Square root both sides: radius = the square root of (area/pi)
If the total area is 42 ft squared then the answer has to be of a number that multiplies to 42 and is more (biggger) than 5...so start with 6x6=36 6x7=42 6x7 is your answer.
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Since the area equals pi times the square of the radius, the radius must be the square root of (the area divided by pi). I got that by dividing both sides of the equation by pi then taking the square root of both sides.
The area of a circle is given by the equation A=πr2.To solve for r, divide both sides by π, then take the square root of both sides of the equation.This leaves you with the equation r=sqrt(A/π)
there are 8 rectangles on a football pitch. There is 3 on both sides for the goals, there are 2 for the outline of the 2 parts and last of all the rectangle that goes around the whole pitch.