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Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

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โˆ™ 2013-03-10 20:49:57
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โˆ™ 2013-03-10 20:49:57

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

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Q: How do you find the unit digit of 312 power 6?
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What is sequence 312?

312 is a single, 3-digit number. It is not a sequence.


Is 312 divisible by 10?

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.


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