Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.
20 = 1
21 = 2
22 = 4
23 = 8
24 = 2
and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...
So if n (mod 3) = 1 the units digit is 2
if n (mod 3) = 2 the units digit is 4
and if n (mod 3) = 0 the units digit is 8
where n (mod 3) is the remainder when n is divided by 3.
312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.
20 = 1
21 = 2
22 = 4
23 = 8
24 = 2
and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...
So if n (mod 3) = 1 the units digit is 2
if n (mod 3) = 2 the units digit is 4
and if n (mod 3) = 0 the units digit is 8
where n (mod 3) is the remainder when n is divided by 3.
312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.
20 = 1
21 = 2
22 = 4
23 = 8
24 = 2
and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...
So if n (mod 3) = 1 the units digit is 2
if n (mod 3) = 2 the units digit is 4
and if n (mod 3) = 0 the units digit is 8
where n (mod 3) is the remainder when n is divided by 3.
312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.
20 = 1
21 = 2
22 = 4
23 = 8
24 = 2
and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...
So if n (mod 3) = 1 the units digit is 2
if n (mod 3) = 2 the units digit is 4
and if n (mod 3) = 0 the units digit is 8
where n (mod 3) is the remainder when n is divided by 3.
312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
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Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.
20 = 1
21 = 2
22 = 4
23 = 8
24 = 2
and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...
So if n (mod 3) = 1 the units digit is 2
if n (mod 3) = 2 the units digit is 4
and if n (mod 3) = 0 the units digit is 8
where n (mod 3) is the remainder when n is divided by 3.
312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
312 is not a sequence: it is a single 3 digit integer and one number cannot define a sequence.
The units digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then it repeats. Since 200 is divisible by 4, the units digit of 3 to the 200th power is 1. So, grab a calculator or trust my sassy math skills, honey, the answer is 1.
52 multiplied by 312 equals 16,224. This is calculated by multiplying the two numbers together using the standard multiplication method, which involves multiplying each digit of the first number by each digit of the second number and then adding up the results. In this case, 52 multiplied by 312 results in 16,224.
2 BA batteries are required to power TA-312 Phone