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Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

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Since neither the three hundred, nor the ten can contribute to the units digit in the answer, you look for a pattern in the units digit in the powers of 2n.

20 = 1

21 = 2

22 = 4

23 = 8

24 = 2

and after that , the pattern repeats, 4, 8, 2, 4, 8, 2, ...

So if n (mod 3) = 1 the units digit is 2

if n (mod 3) = 2 the units digit is 4

and if n (mod 3) = 0 the units digit is 8

where n (mod 3) is the remainder when n is divided by 3.

312 is divisible by 3 [3+1+2=6 is divisible by 3] so 312 mod(3) =0 and so the units digit is 8.

Q: How do you find the unit digit of 312 power 6?

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312 is a single, 3-digit number. It is not a sequence.

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.

312

312 is not a sequence: it is a single 3 digit integer and one number cannot define a sequence.

To solve a question like this, one looks at patterns of powers. For example: 31 = 3 32 = 9 33 = 27 34 = 81 Hence 34 = 1 and 38 = 1 and 312 = 1 and 316 = 1 and so on ............ now in this same sequence 3200 = 1 hence unit digit is 1.

2 BA batteries are required to power TA-312 Phone

312 = 23 x 3 x 13

6. 123, 132, 213, 231, 312, 321.

321 312 213 231 123 132 6 3 digit numbers.

Not possible to convert an area unit (sq meters) to a length unit (feet) If you mean sq feet, then to convert from sq meter to sq feet you divide by (0.3048x0.3048) i.e. 312 sq meters = 312/(0.3048 x 0.3048) sq feet

By unit of length and distance and conversion ,we can say that 1 m=100 cm 3.2 m=320 cm >312 cm 3.2 m >312 cm

274 = (33)4 = 33*4 = 312

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