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LCM(8, 12) = 24


There are two ways:The first, which works best for small numbers, is to write out ppart of the times table for both:

8, 16, 24, 32, 40, ...

12, 24, 36, ...

Look for the smallest number that appears in both tables. It is 24.


However, this is may not work so well if the numbers are very large. So, instead, you write down each of the numbers in terms of its prime factors:

8 = 2*2*2 and 12 = 2*2*3

Next, for any number that appears in both, delete one of the pair - from either set.

8 = 2*2*2 and 12 = 2*2*3 : the first 2 in 12, and the second 2 in 8 have been deleted.

Multiply together all the prime factors that remain: 2*2*2*3 = 24.


The product of the numbers that were deleted is the Highest Common Factor (HCF).

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9y ago

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