8x-7y=42 24x+y=170 An easy way to begin is to solve for one variable in one of your two equations. I will use the second equation to solve for y: 24x+y=170 y=170-24x This solution for y will then be plugged into the first equation so the equation will be of one variable, and therefore solvable: 8x-7y=42 8x-7(170-24x)=42 8x-1190+168x=42 176x=1232 x=1232/176=7 x=7 The solution we made for y can now be used with the solved value of x to find y's numerical value. y=170-24x y=170-24(7) y=170-168 y=2 So, finally, we get that x=7 and y=2
That's where x = 0. Replace x = 0, then solve for "y'.
eqn1 5x - y = -6eqn2 -x + y = 2rearrange eqn1 to isolate yy = -1*(-6-5x)y = 6+5xsubstitute this into eqn2-x + 6 + 5x = 24x + 6 = 24x = -4x = -1substituting this into eqn1-5 -y = -6y = 1
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
This question cannot be answered because there is no graph to tell where the y-intercept is.
8x-7y=42 24x+y=170 An easy way to begin is to solve for one variable in one of your two equations. I will use the second equation to solve for y: 24x+y=170 y=170-24x This solution for y will then be plugged into the first equation so the equation will be of one variable, and therefore solvable: 8x-7y=42 8x-7(170-24x)=42 8x-1190+168x=42 176x=1232 x=1232/176=7 x=7 The solution we made for y can now be used with the solved value of x to find y's numerical value. y=170-24x y=170-24(7) y=170-168 y=2 So, finally, we get that x=7 and y=2
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
That's where x = 0. Replace x = 0, then solve for "y'.
eqn1 5x - y = -6eqn2 -x + y = 2rearrange eqn1 to isolate yy = -1*(-6-5x)y = 6+5xsubstitute this into eqn2-x + 6 + 5x = 24x + 6 = 24x = -4x = -1substituting this into eqn1-5 -y = -6y = 1
Without the y-axis, you don't have a graph.
2 * 2 * 2 * 3 * x * x * x * y * y = 24x^3y^2
If you mean: y = 24x-15 then it is a straight line equation
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
The y-intercept on the graph shows where the graph crosses the y-axis. The value is always the value of y at that point, because x is always equal to zero.
No real roots.
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
The y axis is going up on the graph and the x axis is going sideways on the graph