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If n is an odd integer prove 8 divides n of n-1?
9
Is the sum of one odd number and one even number even or odd prove and explain in words?
The sum of an odd and an even number is odd. Any odd number can be expressed as 2n + 1 (for some integer "n"). Any even number can be expressed as 2m (for another integer, "m"). The sum of the two is 2(m+n) + 1. Since the expression in parentheses is an integer, multiplying it by 2 gives you an even number. Adding 1 makes the entire expression odd.
Is an odd integer greater than 40?
The next odd integer after 40 is 41
What kind of number is 71?
The number 71 is an integer, an odd integer, a positive odd integer, and also a prime number.
Why is the sum of consecutive odd integers always a multiple of 4?
It is quite easy to prove this using algebra. Suppose x is the smaller of the two odd integer. The fact that x is odd means that it is of the form 2m + 1 where m is an integer. [m integer => 2m is an even integer => 2m + 1 is odd] The next odd integer will be x + 2, which is (2m + 1) + 2 = 2m + 3 The sum of these two consecutive odd integers is, therefore, 2m + 1 + 2m + 3 = 4m + 4 = 4(m + 1) Since m is an integer, m+1 is an integer and so 4(m + 1) represents a factorisation of the answer which implies that 4 is a factor of the sum. In other words, the sum is a multiple of 4.
Do Prove that the product of an integer and arbitrary integer is even?
The statement is not true. Disprove by counter-example: 3 is an integer and 5 is an integer, their product is 15 which is odd.
What are the three consecutive odd integers with sum of -30?
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
How do you use inductive reasoning to prove the product of an odd integer and an even integer will always be even?
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
If n is an odd integer prove 8 divides n of n-1?
9
What is the 17th odd positive integer?
33 The 17th odd positive integer is
Is the sum of one odd number and one even number even or odd prove and explain in words?
The sum of an odd and an even number is odd. Any odd number can be expressed as 2n + 1 (for some integer "n"). Any even number can be expressed as 2m (for another integer, "m"). The sum of the two is 2(m+n) + 1. Since the expression in parentheses is an integer, multiplying it by 2 gives you an even number. Adding 1 makes the entire expression odd.
Is -2 even integer or odd integer?
even integer.
Is an odd integer greater than 40?
The next odd integer after 40 is 41
What kind of number is 71?
The number 71 is an integer, an odd integer, a positive odd integer, and also a prime number.
Are decimals odd or even?
Only integers are even or odd. We do not call fractions, irrational numbers, imaginary numbers, and so on either even or odd. If a decimal is equal to an integer (for example 24.0 is equal to 24), then it is even if the integer is even or odd if the integer is odd. If a decimal is not equal to an integer (for example 24.1 is not an integer), then it is neither even nor odd.
Why is the sum of consecutive odd integers always a multiple of 4?
It is quite easy to prove this using algebra. Suppose x is the smaller of the two odd integer. The fact that x is odd means that it is of the form 2m + 1 where m is an integer. [m integer => 2m is an even integer => 2m + 1 is odd] The next odd integer will be x + 2, which is (2m + 1) + 2 = 2m + 3 The sum of these two consecutive odd integers is, therefore, 2m + 1 + 2m + 3 = 4m + 4 = 4(m + 1) Since m is an integer, m+1 is an integer and so 4(m + 1) represents a factorisation of the answer which implies that 4 is a factor of the sum. In other words, the sum is a multiple of 4.
Is the square of an odd integer is odd?
Yes.
