Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.
Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.
Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.
Solve for y; calculate a few sample points (plug in a value for x, then calculate the corresponding value for y); plot on the graph. Two points should be enough in theory (this equation is a straight line), but a third point helps you confirm that your calculations are correct.
-2x plus 3y equals 1
7
39.0625 is.
it equals 13X.
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
-2x plus 3y equals 1
7
No.
2,4
k
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
A graph that has 1 parabolla that has a minimum and 1 positive line.
(0,4) and (-2, 0)
39.0625 is.
it equals 13X.
y=-10x-4
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3