If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1
x+3y=2 x= -5 y = 1
Solve for y 3y=-7x+9 y=-7/3x+3 the slope is the coefficient of x in this case, it is -7/3
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
4x-5y=20 x-3y=10 becomes x=3y-10 plug that into the first equation: 4(3y-10)-5y=20 12y-40-5y=20 7y=60 y=60/7 If x=3y-10, then x=3(60/7)-10 x=180/7 - 70/7 x=110/7
If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1
4x + 3y = 7 y = [(-4)/3] x + 7/3
x+3y=2 x= -5 y = 1
Divide all terms by -3 then it will be in slope intercept form
Solve for y 3y=-7x+9 y=-7/3x+3 the slope is the coefficient of x in this case, it is -7/3
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
4x-5y=20 x-3y=10 becomes x=3y-10 plug that into the first equation: 4(3y-10)-5y=20 12y-40-5y=20 7y=60 y=60/7 If x=3y-10, then x=3(60/7)-10 x=180/7 - 70/7 x=110/7
x=2 y=7 5x+3y= 5 7 x 2 x 3 ____ _____ 10 21 21 + 10 _______ 31
Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
given is that 4x+3y=6(3x+3y)=7 i.e., 6(3x+3y)=7 &&& 4x+3y=7 ---------------(1) 3x+3y=7/6 x+y=7/18 _________(2) multiply eqn(2) by 4 4x+4y=28/18 -------------------------(3) (3)-(1) 4x+3y-4x-4y=7-(28/18) y= -98/18 substitute y in eqn(2) x-98/18=7/18 x=7/18+98/18 x=105/18. therefore x=105/18 : y= -98/18
-4