If: 3x-4 = or > 11 Then: 3x = or > 15 So: x = or > 5
4x+7-3x = 15 4x-3x = 15-7 x = 8
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
-3x + 5 = 20 -3x = 15 x = -5
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
If: 3x-4 = or > 11 Then: 3x = or > 15 So: x = or > 5
4x+7-3x = 15 4x-3x = 15-7 x = 8
4
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
3x-8>15
-3x + 5 = 20 -3x = 15 x = -5
3x-5y=15 The equation-5y=15-3x Subtract 3x from both sidesy=-3+.6x Divide both sides by -5
x + 5 = 4x/3 Solve for x multiply both sides of the equation by 3... 3 * (x + 5) = 3 * (4x/3) 3x + 15 = 4x subtract 3x from both sides of the equation (3x + 15) - 3x = (4x) - 3x 15 = x x = 15
Treat the "greater than" sign as an equal sign, so subtract 3 from 12 and you get 9. Divide the 9 by three and you get 3. You should get x > 3.
"x3" is not an inequality. An inequality will have one of the following signs: less-than, less-than-or-equal, greater-than, greater-than-or-equal. for example: 3x - 5 < 15
3x + 5 = 20 Subtract '5' from both sides 3x = 15 Divide both sides by '3' x = 5 The answer!!!!!
Since there are no brackets or parentheses, the divisions must be evaluated from left to write so that the expression is ((25/5x)/15)/3x = ((5/x)/15)/3x = (5/15x)/3x = (1/3x)/3x = 1/(9x2)