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(x-3)^2 = - 12

x - 3 = +/- sqrt(-12)

x = 3 + sqrt(-12) or x = 3 - sqrt(-12)

Your answer will contain an imaginary part for both values of x, which is either plus or minus the square root of-12.

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12y ago
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Q: How do you solve X-3 in parentheses squared equals -12?
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