0
-23
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Rene
Professor
Add your answer:
Earn +20 pts
How do you factor you-v2-you v2?
You don't. You solve it. u - v^2 - u + v^2 = 0
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
How do you solve 2 16 over 25?
2 16/25 = 2.64
How do you solve 2.12 and make it into a fraction?
There is nothing to solve! 2.12 = 212/100 = 53/25
How do you solve 60.5 multipyed by 25 percent?
25% = 0.2560.5 x 0.25 = 15.125
How do you solve boyles law equation for V2?
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
How do you factor you-v2-you v2?
You don't. You solve it. u - v^2 - u + v^2 = 0
How do you factor 100V square minus 25W square?
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
What will be the final volume of a solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40?
The final volume of the solution will be 68.18 mL. This can be calculated using the formula for dilution, which is M1V1 = M2V2. Solving for V2 (final volume) gives V2 = (M1V1) / M2 = (8.25 M * 25 mL) / 2.40 M = 68.18 mL.
How do you solve 25 by 3.14?
type in 25/pi
Which missile was bigger V1 or V2?
the V2 rocket was bigger and faster than the V1 flying bomb. the V1 being a flying bomb was smaller and had a pulse jet engine and the V2 which was a rocket had a bigger rocket engine. ACTUAL SIZE COMPARISON: V1: Length: 25' 4" wingspan: 8.32 meters V2: length 14 m (45 ft 11 in)
How do you solve 2 16 over 25?
2 16/25 = 2.64
If you initially have a gas at a pressure of 12 ATM a volume of 23 liters and then you raise the pressure to 14 ATM what is the new volume of the gas?
The volume of the gas will decrease proportionally to the increase in pressure, following Boyle's Law. Using the formula P1V1 = P2V2, where P1 = 12 ATM, V1 = 23 L, and P2 = 14 ATM, we can solve for V2 to find the new volume of the gas. Solving for V2 gives V2 = (P1)(V1) / P2 = (12)(23) / 14 = 19.71 liters.
What is the volume of the gas at 200 degrees c if it is 25 L at 0 degrees c?
To calculate the volume of a gas at a different temperature, you can use the formula: (V2 = V1 * (T2 / T1)), where V1 is the initial volume (25 L), T1 is the initial temperature (273 K for 0 degrees Celsius), T2 is the final temperature (473 K for 200 degrees Celsius). Plugging these values into the formula, you get V2 = 25 * (473 / 273) = 43.57 L. Therefore, the volume of the gas at 200 degrees Celsius is approximately 43.57 L.
9.00m3 of a gas at constant temperature has a pressureof 0.93atm what is its volume at standard pressure?
Using the ideal gas law (PV = nRT) and since the temperature is constant, the initial and final conditions of the gas can be related through (P1V1) = (P2V2). Given: P1 = 0.93 atm V1 = 9.00 m^3 P2 = 1 atm (standard pressure) V2 = unknown Rearranging the equation to solve for V2 gives: V2 = (P1V1) / P2 Substitute the values and solve: V2 = (0.93 atm * 9.00 m^3) / 1 atm V2 = 8.37 m^3 Therefore, the volume of the gas at standard pressure is 8.37 m^3.
How do you solve 2.12 and make it into a fraction?
There is nothing to solve! 2.12 = 212/100 = 53/25
