This is not an equation.
If you mean v2 - 25 = 0 , the solution set is {5, -5}.
You don't. You solve it. u - v^2 - u + v^2 = 0
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
2 16/25 = 2.64
There is nothing to solve! 2.12 = 212/100 = 53/25
25% = 0.2560.5 x 0.25 = 15.125
You don't. You solve it. u - v^2 - u + v^2 = 0
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
For all dilution/ concentration problems you use the simple equation: M1V1 = M2V2 2.40*V2 = 8.25*25 V2 = (8.25*25)/2.40 V2 = 85.9mL Final volume will be 86mL.
Use the combined gas law and solve. (PV/T)1 = (PV/T)2 P1 = 1201 torr, V1 = 40L, T1= 50C = 323K must be kelvin for gas laws STP implies P2 = 760 torr, T2 = 273K, V2 is the unknown Substitute and solve.... (1201x50 / 373) = (760 V2 / 273) rearrange with algebra and solve V2 = (1201x50x273)/(373x760) answer will be in liters
Depends on the voltage. R equals V2/P . Or the current: R equals P/I2 .
type in 25/pi
P1V1 = P2V2 P1 = 2atm V1 = xmL P2 = 3atm V2 = ? Solve for V2: P1V1/P2 = V2 (2atm)(x mL)/3atm = 2/3x mL
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
the V2 rocket was bigger and faster than the V1 flying bomb. the V1 being a flying bomb was smaller and had a pulse jet engine and the V2 which was a rocket had a bigger rocket engine. ACTUAL SIZE COMPARISON: V1: Length: 25' 4" wingspan: 8.32 meters V2: length 14 m (45 ft 11 in)
2 16/25 = 2.64
There is nothing to solve! 2.12 = 212/100 = 53/25