-23
You don't. You solve it. u - v^2 - u + v^2 = 0
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
2 16/25 = 2.64
There is nothing to solve! 2.12 = 212/100 = 53/25
25% = 0.2560.5 x 0.25 = 15.125
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
You don't. You solve it. u - v^2 - u + v^2 = 0
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
For all dilution/ concentration problems you use the simple equation: M1V1 = M2V2 2.40*V2 = 8.25*25 V2 = (8.25*25)/2.40 V2 = 85.9mL Final volume will be 86mL.
type in 25/pi
the V2 rocket was bigger and faster than the V1 flying bomb. the V1 being a flying bomb was smaller and had a pulse jet engine and the V2 which was a rocket had a bigger rocket engine. ACTUAL SIZE COMPARISON: V1: Length: 25' 4" wingspan: 8.32 meters V2: length 14 m (45 ft 11 in)
2 16/25 = 2.64
The volume of the gas will decrease proportionally to the increase in pressure, following Boyle's Law. Using the formula P1V1 = P2V2, where P1 = 12 ATM, V1 = 23 L, and P2 = 14 ATM, we can solve for V2 to find the new volume of the gas. Solving for V2 gives V2 = (P1)(V1) / P2 = (12)(23) / 14 = 19.71 liters.
There is nothing to solve! 2.12 = 212/100 = 53/25
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
Using the ideal gas law (PV = nRT) and since the temperature is constant, the initial and final conditions of the gas can be related through (P1V1) = (P2V2). Given: P1 = 0.93 atm V1 = 9.00 m^3 P2 = 1 atm (standard pressure) V2 = unknown Rearranging the equation to solve for V2 gives: V2 = (P1V1) / P2 Substitute the values and solve: V2 = (0.93 atm * 9.00 m^3) / 1 atm V2 = 8.37 m^3 Therefore, the volume of the gas at standard pressure is 8.37 m^3.