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What else can I help you with?
How do you factor you-v2-you v2?
You don't. You solve it. u - v^2 - u + v^2 = 0
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
How do you solve 2 16 over 25?
2 16/25 = 2.64
How do you solve 2.12 and make it into a fraction?
There is nothing to solve! 2.12 = 212/100 = 53/25
How do you solve 60.5 multipyed by 25 percent?
25% = 0.2560.5 x 0.25 = 15.125
How do you solve boyles law equation for V2?
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
How do you factor you-v2-you v2?
You don't. You solve it. u - v^2 - u + v^2 = 0
How do you factor 100V square minus 25W square?
100 V2 - 25 W2 = (10V + 5W) (10V - 5W)Another way to show it:100 V2 - 25 W2 = 25 (4 V2 - W2) = 25 (2V - W) (2V + W)
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
What will be the final volume of a solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40?
For all dilution/ concentration problems you use the simple equation: M1V1 = M2V2 2.40*V2 = 8.25*25 V2 = (8.25*25)/2.40 V2 = 85.9mL Final volume will be 86mL.
How do you solve 25 by 3.14?
type in 25/pi
Which missile was bigger V1 or V2?
the V2 rocket was bigger and faster than the V1 flying bomb. the V1 being a flying bomb was smaller and had a pulse jet engine and the V2 which was a rocket had a bigger rocket engine. ACTUAL SIZE COMPARISON: V1: Length: 25' 4" wingspan: 8.32 meters V2: length 14 m (45 ft 11 in)
What is the volume of the gas at 200 degrees c if it is 25 L at 0 degrees c?
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
If you initially have a gas at a pressure of 12 ATM a volume of 23 liters and then you raise the pressure to 14 ATM what is the new volume of the gas?
The volume of the gas will decrease proportionally to the increase in pressure, following Boyle's Law. Using the formula P1V1 = P2V2, where P1 = 12 ATM, V1 = 23 L, and P2 = 14 ATM, we can solve for V2 to find the new volume of the gas. Solving for V2 gives V2 = (P1)(V1) / P2 = (12)(23) / 14 = 19.71 liters.
How do you solve 2 16 over 25?
2 16/25 = 2.64
9.00m3 of a gas at constant temperature has a pressureof 0.93atm what is its volume at standard pressure?
Using the ideal gas law (PV = nRT) and since the temperature is constant, the initial and final conditions of the gas can be related through (P1V1) = (P2V2). Given: P1 = 0.93 atm V1 = 9.00 m^3 P2 = 1 atm (standard pressure) V2 = unknown Rearranging the equation to solve for V2 gives: V2 = (P1V1) / P2 Substitute the values and solve: V2 = (0.93 atm * 9.00 m^3) / 1 atm V2 = 8.37 m^3 Therefore, the volume of the gas at standard pressure is 8.37 m^3.
How do you use a 100 ppm dilution to achieve 25ml of a 10 ppm dilution?
To prepare a 10 ppm dilution from a 100 ppm stock solution, you can use the dilution equation: C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock needed, C2 is the desired concentration, and V2 is the final volume. Here, C1 is 100 ppm, C2 is 10 ppm, and V2 is 25 ml. Rearranging the equation to solve for V1 gives you V1 = (C2 * V2) / C1 = (10 ppm * 25 ml) / 100 ppm = 2.5 ml. Therefore, you need to take 2.5 ml of the 100 ppm solution and dilute it with 22.5 ml of solvent (water or another appropriate diluent) to achieve a total volume of 25 ml at 10 ppm.
