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The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
What else can I help you with?
Solve 2x plus 3 equals 7?
2x+3 = 7 2x = 7-3 2x = 4 x = 2
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
How do you solve 3x plus 4 equals 2x - 3?
3x+4 = 2x-3 3x-2x = -3-4 x = -7
How do you solve 2x plus 3 equals 9X equals?
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
Solve this problem 2x plus 3 equals 9 what is x?
2x + 3 = 9 To solve Subtract '3' from both sides 2x = 6 Divide both sides by '2' x = 3 The Answer!!!!!
Solve 2x plus 3 equals 9?
3
Solve 2x-3 equals 9?
2x-3=9 so 2x=12 and x=6
Solve 2x plus 3 equals 7?
2x+3 = 7 2x = 7-3 2x = 4 x = 2
How do you solve 2x plus 3 equals negative 11?
2x+3 = -11 2x = -11-3 2x = -14 x = -7
Solve X3 plus X2-8X-6 equals 0?
x3 + x2 - 8x - 6 = 0 x3 + 3x2 - 2x2 - 6x - 2x - 6 = 0 x2(x + 3) - 2x(x + 3) - 2(x + 3) = 0 (x + 3)(x2 - 2x - 2) = 0 The second bracket cannot be factorised, so applying the quadratic formula to it gives the answers as So x = -3 or x = 1 +/-sqrt(3) that is, x = -3, x = -0.732051 or x = 2.732051
How do you solve 2x-y equals -6 and 2x plus 3y equals 9?
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Solve 2x plus 3 equals 9 x equals?
2x+3=9x 3=9x-2x 3=7x x=3/7
How do you solve 3x plus 4 equals 2x - 3?
3x+4 = 2x-3 3x-2x = -3-4 x = -7
How do you solve 4x2-2x-3 equals 0?
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
How do you solve 2x plus 3 equals 9X equals?
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
How do you solve x plus 2x equals 3?
2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3
How do you solve the equation 3x-2 equals 2x plus 3?
3x-2 = 2x+3 3x-2x = 3+2 x = 5
