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The second "equation" is, in fact, two equations, and the three equations are inconsistent.

The "second" equation gives :

2x = 3 so that x = 3/2 and also y = 3

But substituting these values in the first equation implies that 3 = (3/2) - 3

or 3 = 3/2 or 2 = 1 which is a contradiction.

The second "equation" is, in fact, two equations, and the three equations are inconsistent.

The "second" equation gives :

2x = 3 so that x = 3/2 and also y = 3

But substituting these values in the first equation implies that 3 = (3/2) - 3

or 3 = 3/2 or 2 = 1 which is a contradiction.

The second "equation" is, in fact, two equations, and the three equations are inconsistent.

The "second" equation gives :

2x = 3 so that x = 3/2 and also y = 3

But substituting these values in the first equation implies that 3 = (3/2) - 3

or 3 = 3/2 or 2 = 1 which is a contradiction.

The second "equation" is, in fact, two equations, and the three equations are inconsistent.

The "second" equation gives :

2x = 3 so that x = 3/2 and also y = 3

But substituting these values in the first equation implies that 3 = (3/2) - 3

or 3 = 3/2 or 2 = 1 which is a contradiction.

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11y ago
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Wiki User

11y ago

The second "equation" is, in fact, two equations, and the three equations are inconsistent.

The "second" equation gives :

2x = 3 so that x = 3/2 and also y = 3

But substituting these values in the first equation implies that 3 = (3/2) - 3

or 3 = 3/2 or 2 = 1 which is a contradiction.

This answer is:
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Q: How do you solve y equals x-3 and 2x equals y equals 3?
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