The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
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The second "equation" is, in fact, two equations, and the three equations are inconsistent.
The "second" equation gives :
2x = 3 so that x = 3/2 and also y = 3
But substituting these values in the first equation implies that 3 = (3/2) - 3
or 3 = 3/2 or 2 = 1 which is a contradiction.
2x+3 = 7 2x = 7-3 2x = 4 x = 2
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
3x+4 = 2x-3 3x-2x = -3-4 x = -7
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
2x + 3 = 9 To solve Subtract '3' from both sides 2x = 6 Divide both sides by '2' x = 3 The Answer!!!!!