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Although it does not allow for factors such as air resistence, perhaps it's the formula
s = (iVt) + ( (1/2)at2)
where s is Distance, iV is initial velocity, t is time (t2 is time squared) and a is acceleration.
Taking 0 as the initial velocity, 1 second as the change in time, 9.8 m/s as the acceleration (as it is near the earth's surface):
s = ( 0(1) ) + ( (1/2)(9.8)(12) )
s = 4.9
The object will fall by 4.9 metres.
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