How far does an object fall in one second?

Answer 1

The distance an object falls in one second can be calculated using the formula d = 1/2 * g * t^2, where d is the distance, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds (in this case, 1 second). Plugging in the values, we get d = 1/2 * 9.81 * 1^2 = 4.905 meters. Therefore, an object would fall approximately 4.905 meters in one second under the influence of gravity.

Answer 2

Well, honey, let me break it down for you. In one second, an object in free fall will travel approximately 4.9 meters on Earth. So, if you drop something, just remember it's gonna hit the ground pretty darn quickly. Keep that in mind next time you're playing catch with your friends!

Answer 3

Although it does not allow for factors such as air resistence, perhaps it's the formula

s = (iVt) + ( (1/2)at2)

where s is Distance, iV is initial velocity, t is time (t2 is time squared) and a is acceleration.

Taking 0 as the initial velocity, 1 second as the change in time, 9.8 m/s as the acceleration (as it is near the earth's surface):

s = ( 0(1) ) + ( (1/2)(9.8)(12) )

s = 4.9

The object will fall by 4.9 metres.

Answer 4

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