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How many 3 digit number are such that their first digit equals the sum of the last two digit?

Updated: 12/22/2022

Wiki User

10y ago

There are 54 such numbers.

There are 54 such numbers.

There are 54 such numbers.

There are 54 such numbers.

Wiki User

10y ago
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A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Wiki User

10y ago

There are 54 such numbers.

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Q: How many 3 digit number are such that their first digit equals the sum of the last two digit?
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How do you multiply a three-digit number by a two-digit number?

Multiply the three-digit number by the one's digit, or last digit, of the two-digit number. That is your first part. Now multiply by the second-to-last digit, or ten's digit, and multiply the result by 10. That is your second part. Add the two parts and that is your answer.

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The answer is 4559 Sum of the two digit 7+2=9 is the last digit difference of the two digit is last second digit 7-2=5 And the product of these last two digits 9*5=45 forms the first two digit So the answer is 4559

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