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Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
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∙ 2013-07-15 01:05:20
Siyath Atapattu
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How many four digit palindromical numbres?
The first digit can be any one of nine (all except zero). For each of those . . .The second digit can be any one of ten.Total possibilities for the first two digits = 9 x 10 = 90.Since the 4-digit number is a palindrome, the 3rd and 4th digits are determinedby the 1st and 2nd ones.So the total number of 4-digit palindromes is the same as the number of possibilitiesfor the first 2 digits = 90 .
What multiples of 2 end in?
even numbers, specifically the last digit is 0, 2, 4, 6, or 8.
What are four digit multiples of 4?
1000, 1004, 1008 and just keep adding four until you get to 9996.
What are the two digit number less than 15 that is a multiple of 4?
12 is the only number which satisfies this. Multiples of 4 are: 4, 8, 12, 16, . . . .
How many 2 digit numbers contain the digit 4?
17
How many 5-digit palindromes are multiples of 9?
-4
How many 4-digit palindromes are there?
There are 90 four-digit palindromes
How many 4-digit numbers are palindromes?
There are 90 such numbers.
How many 4 digit numbers that are multiples of 9?
999
What digits are always the same in a 4-digit palindrome?
None. 1221 and 3443 are both 4-digit palindromes but no digit has remained the same between the two. First and fourth, second and third.
How many 4 digit numbers are palindromes?
There are 90 palindromes with 4 digits.The first digit can be any digit from the set {1,2,3,4,5,6,7,8,9}.With each choice of the first digit, the second can be any digit from the set {0,1,2,3,4,5,6,7,8,9}.That makes 9*10 = 90 permutations for the first two digits. These determine the palindrome since the third and fourth digits are the same as the second and first, respectively.
How many four-digit counting numbers are not multiples of 4?
There are 6,750 such numbers.
How many 2 digit whole numbers are multiples of both 6 and 4?
8 of them.
How many different three digit palindromes can you make using only the digits 1and 2?
There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.
How many palindromes are there between 900 - 1900?
-1000
How many 5 digit palindromes are there?
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
How many 3 digit numbers are divisible by 4 and 6?
There are 75 multiples of 12 between 100 and 1000.
