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90 four-digit palindromes are divisible by 9.

4 four-digit palindromes are divisible by 18

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Michaela Chong

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2y ago

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Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.

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Wiki User

11y ago
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Siyath Atapattu

Lvl 1
3y ago
Nope there is also 9999 so there is 10

There are 90 4 dight ones

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Yui Ichika

Lvl 2
3y ago
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Edyth Anderson

Lvl 1
3y ago
great answer tyyy

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Q: How many 4 digit palindromes are multiples of 9?
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